SWEA 4112. 이상한 피라미드 탐험
bfs
- 6방향이 있고, depth를 통해 계산할 수 있다.
- 최소 시간을 구해야 하기 때문에 bfs를 이용한다.
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#include <cstdio>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <string>
using namespace std;
#define MAX_N 10005
int tc;
int from, to;
int res;
int depth[MAX_N];
bool visited[MAX_N];
void init() {
memset(visited, 0, sizeof(visited));
scanf("%d%d", &from, &to);
}
void prepare() {
int i = 1;
int curDepth = 1;
while (i < MAX_N) {
for (int j = 0; j < curDepth; i++, j++) {
if (i >= MAX_N) break;
depth[i] = curDepth;
}
curDepth++;
}
}
int bfs() {
queue<int> q;
q.push(from);
visited[from] = true;
int cnt = 0;
while (!q.empty()) {
int qSize = q.size();
for (int qs = 0; qs < qSize; qs++) {
int cur = q.front();
q.pop();
if (cur == to)
return cnt;
int next;
// left-top
next = cur - depth[cur];
if (!visited[next] && depth[next] == depth[cur] - 1) {
visited[next] = true;
q.push(next);
}
// right-top
next = cur - depth[cur] + 1;
if (!visited[next] && depth[next] == depth[cur] - 1) {
visited[next] = true;
q.push(next);
}
// left
next = cur - 1;
if (!visited[next] && depth[next] == depth[cur]) {
visited[next] = true;
q.push(next);
}
// right
next = cur + 1;
if (!visited[next] && depth[next] == depth[cur]) {
visited[next] = true;
q.push(next);
}
// left-bottom
next = cur + depth[cur];
if (!visited[next] && depth[next] == depth[cur] + 1) {
visited[next] = true;
q.push(next);
}
// right-bottom
next = cur + depth[cur] + 1;
if (!visited[next] && depth[next] == depth[cur] + 1) {
visited[next] = true;
q.push(next);
}
}
cnt++;
}
return 0;
}
int main() {
prepare();
int testcase;
scanf("%d", &testcase);
for (tc = 1; tc <= testcase; tc++) {
init();
printf("#%d %d\n", tc, solution());
}
}