BOJ 1755. 숫자놀이
    sort
    - 숫자의 영단어를 String 배열에 저장
 - 문자열을 사전순으로 정렬하는 compareTo() override
 
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
 
import java.util.*;
import java.io.*;
public class Main {
	static int M, N;
	static class Node implements Comparable<Node> {
		int num;
		String str;
		Node(int num, String str) {
			this.num = num;
			this.str = str;
		}
		@Override
			public int compareTo(Node o) {
				return this.str.compareTo(o.str);
			}
	}
	static void solution() {
		List<Node> list = new ArrayList<>();
		for (int i = M; i <= N; i++) {
			StringBuilder sb = new StringBuilder();
			char[] numStr = Integer.toString(i).toCharArray();
			for (int j = 0; j < numStr.length; j++)
				sb.append(map[numStr[j] - '0']).append(" ");
			sb.setLength(sb.length()-1);
			list.add(new Node(i, sb.toString()));
		}
		Collections.sort(list);
		StringBuilder out = new StringBuilder();
		for (int i = 0, cnt = 0; i < list.size(); i++, cnt++) {
			String last = " ";
			if (cnt == 9) {
				last = "\n";
				cnt = -1;
			}
			out.append(list.get(i).num).append(last);
		}
		System.out.print(out);
	}
	static String[] map = {"zero", "one", "two", "three", "four",
		"five", "six", "seven", "eight", "nine"};
	public static void main(String[] args) throws Exception {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st = new StringTokenizer(in.readLine(), " ");
		M = Integer.parseInt(st.nextToken());
		N = Integer.parseInt(st.nextToken());
		solution();
	}
}